y^2-22y+120=0

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Solution for y^2-22y+120=0 equation:


Simplifying
y2 + -22y + 120 = 0

Reorder the terms:
120 + -22y + y2 = 0

Solving
120 + -22y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(10 + -1y)(12 + -1y) = 0

Subproblem 1

Set the factor '(10 + -1y)' equal to zero and attempt to solve: Simplifying 10 + -1y = 0 Solving 10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1y = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1y = 0 + -10 -1y = 0 + -10 Combine like terms: 0 + -10 = -10 -1y = -10 Divide each side by '-1'. y = 10 Simplifying y = 10

Subproblem 2

Set the factor '(12 + -1y)' equal to zero and attempt to solve: Simplifying 12 + -1y = 0 Solving 12 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1y = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1y = 0 + -12 -1y = 0 + -12 Combine like terms: 0 + -12 = -12 -1y = -12 Divide each side by '-1'. y = 12 Simplifying y = 12

Solution

y = {10, 12}

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